Linear Algebra and the C Language/a0n8
The spectral decomposition:
Matrix A and the inverse matrix of A have the same eigenvectors but arranged in reverse order
The application
b1r1 + b2r2 + b3r3 = Ide (The b_r_ are projectors.)
- c00b.c
- b*: The columns of the eigenvectors of A
- r*: The rows of eigenvectors of the inverse of A
E1 b1r1 + E2 b2r2 + E3 b3r3 = A
- c00c.c
- E*: The eignvalues of A
b1r1**2 = b1r1; ... ... ... b1r1**3 = b1r1; ... ... ... b1r1**P = b1r1;
- c00d.c
- Several consecutive projections, (b_r_**P), give the same result
b1r1 * b3r3 = 0; ... ... ... b1r1 * b2r2 = 0; ... ... ... b2r2 * b3r3 = 0;
- c00e.c
- The projectors b_r_ are orthogonal to each other
E1**2 b1r1 + E2**2 b2r2 + E3**2 b3r3 = A**2
- c00f.c
- Calculate the power n of A with the power n of each of the eigenvalues
1/E1 b1r1 + 1/E2 b2r2 + 1/E3 b3r3 = inv(A)
- c00g.c
- Calculate the inverse of A with the inverse of each of the eigenvalues