Linear Algebra and the C Language/a0jn


Install and compile this file in your working directory.

/* ------------------------------------ */
/*  Save as :   c00b.c                  */
/* ------------------------------------ */
#include "v_a.h"
/* ------------------------------------ */
#define   RA R5
#define   CA C5    
/* ------------------------------------ */
int main(void)
{
double xy[6] ={
   1,     -1,
   2,     -9,
   3,     -8    };
   
double tA[RA*CA]={
/* x**2     y**2     x        y        e     */
  +1,      +0,      +0,      +0,      +0,       
  +0,      +1,      +0,      +0,      +0,       
  +1,      +1,      +1,      -1,      +1,        
  +4,     +81,      +2,      -9,      +1,       
  +9,     +64,      +3,      -8,      +1,       
};

double tb[RA*C1]={
/*   = 0   */
      +1,   
      +1,   
      +0,   
      +0,   
      +0,  
};

double **XY      = ca_A_mR(xy,i_mR(R3,C2));
double **A       = ca_A_mR(tA,i_mR(RA,CA));
double **b       = ca_A_mR(tb,i_mR(RA,C1));
double **Inv    = i_mR(CA,RA);           
double **Invb   = i_mR(CA,C1);          

  clrscrn();
  printf("\n");
  printf(" Find the coefficients a, b, c, d,  of a circle  \n\n");
  printf("     ax**2 + ay**2 + bx + cy + d  = 0            \n\n");
  printf(" that passes through these three XY.         \n\n");
  printf("    x     y");
  p_mR(XY,S5,P0,C6);
  stop();
  
  clrscrn(); 
  printf(" Using the given XY, we obtain this matrix.\n");
  printf("  (a = 1. This is my choice)\n\n");
  printf(" A :");
  p_mR(A,S10,P2,C7);
  printf(" b :");
  p_mR(b,S10,P2,C7);
   
  printf(" Inv :");
  invgj_mR(A,Inv); 
  pE_mR(Inv,S12,P4,C10); 
  stop();
  
  clrscrn(); 
  printf(" Inv :"); 
  p_mR(Inv,S10,P4,C10);  
  
  printf(" x = Inv * b ");   
  mul_mR(Inv,b,Invb); 
  p_mR(Invb,S10,P4,C10);
  printf(" The coefficients a, b, c, d, e, of the curve are : \n\n"
         "  %+.2fx**2 %+.2fy**2 %+.2fx %+.2fy %+.2f = 0\n\n"
            ,Invb[R1][C1],Invb[R2][C1],Invb[R3][C1],
             Invb[R4][C1],Invb[R5][C1]);       
  stop(); 
   
  f_mR(XY);    
  f_mR(A);
  f_mR(b); 
  f_mR(Inv);
  f_mR(Invb); 
  
  return 0;
}
/* ------------------------------------ */
/* ------------------------------------ */


Screen output example:
 Find the coefficients a, b, c, d,  of a circle  

     ax**2 + ay**2 + bx + cy + d  = 0            

 that passes through these three XY.         

    x     y
   +1    -1 
   +2    -9 
   +3    -8 

 Press return to continue. 


 Using the given XY, we obtain this matrix.
  (a = 1. This is my choice)

 A :
     +1.00      +0.00      +0.00      +0.00      +0.00 
     +0.00      +1.00      +0.00      +0.00      +0.00 
     +1.00      +1.00      +1.00      -1.00      +1.00 
     +4.00     +81.00      +2.00      -9.00      +1.00 
     +9.00     +64.00      +3.00      -8.00      +1.00 

 b :
     +1.00 
     +1.00 
     +0.00 
     +0.00 
     +0.00 

 Inv :
 +1.0000e+00  +4.9960e-16  -6.9389e-18  +1.7347e-17  +2.4286e-17 
 -6.9389e-18  +1.0000e+00  +3.4266e-19  -1.7240e-18  +2.2701e-18 
 -4.7778e+00  +6.2222e+00  -1.1111e-01  -7.7778e-01  +8.8889e-01 
 -2.2222e-01  +1.0778e+01  +1.1111e-01  -2.2222e-01  +1.1111e-01 
 +3.5556e+00  +3.5556e+00  +1.2222e+00  +5.5556e-01  -7.7778e-01 

 Press return to continue. 


 Inv :
   +1.0000    +0.0000    -0.0000    +0.0000    +0.0000 
   -0.0000    +1.0000    +0.0000    -0.0000    +0.0000 
   -4.7778    +6.2222    -0.1111    -0.7778    +0.8889 
   -0.2222   +10.7778    +0.1111    -0.2222    +0.1111 
   +3.5556    +3.5556    +1.2222    +0.5556    -0.7778 

 x = Inv * b 
   +1.0000 
   +1.0000 
   +1.4444 
  +10.5556 
   +7.1111 

 The coefficients a, b, c, d, e, of the curve are : 

  +1.00x**2 +1.00y**2 +1.44x +10.56y +7.11 = 0

 Press return to continue.


Copy and paste in Octave:
function xy = f (x,y)
  xy = +0.999999988*x^2 +1.000000219*y^2 +1.444445879*x +10.555557922*y +7.111111809;
endfunction

f (+1,-1) 
f (+2,-9) 
f (+3,-8)